In this paper, we prove: if ak-j(j=1,…,k) are polynomials, deg ak-j=nk-j, there exists some ak-s(1≤s≤k) such that nk-j/j≤nk-s/s if 1≤jk-j< nk-s- ( j - s) if s < j ≤ k , if F≠0 is an entire function satisfying σ(F)=β<(nk-s+s)/s, then a so lution of the differential equat ion f(k)+ak-1f(k-1)+…+a0f=Fsat isf ies λ(f)=λ(f)=σ(f)=(nk-s+s)/s,or σ(f)=β. |